Total current load = Total connected load / voltage ratingĢ. Solve for the total load of circuit 1 to circuit 3. Continuing the solution, we have the following:ġ. The size of service entrance being the supply conductor and equipment for delivering energy from the electricity supply to the wiring system of the building, is also computed based on the total load supplied by the branch circuit. Therefore, the 20 amperes fuse over current protection is accepted. Granting that it will be derated at 80 % x 20, the 16 amperes derated value is still higher than the computed load of 15.65 amperes.
For the 15.65 amperes load use 20 amperes fuse rating. Determine the size or rating of the Over-current Protection. 12 AWG wire can be accommodated comfortably in a 13 mm diameter conduit pipe. Determine the Size of the Conduit Pipe (if reqd) to Table. For the 15.65 amperes load, use 2 pieces 3.5 mm 2 or No.12 AWG TW copper wireĥ. Determine the size of the service conductor wire. Examining Figure above, other loads are:ġ - unit electric stove at 1.1 kw = 1,1oo wattsġ - unit water heater at 2.5 kw = 2,500 wattsģ. 12 AWG copper wire as the minimum size for all types of convenience outlet wiring except, for an appliance with limited load wherein a 2.0 mm 2or No.14 AWG wire is permitted.ġ.
ELECTRICDESIGN CODE
14 AWG wire conductor could safely carry the 9.36 amperes computed load, considering its 15 amperes ampacity rating,yet, we cannot do so because the Code specifically mandated the use of 3.5 mm 2or No. Granting that only 80 % of this 15 amperes is considered the derated value, still 12 amperes is very much larger than the 9.36 amperes computed as maximum load for 6-convenience outlet. 14 AWG TW copper wire has an allowable ampacity rating of 15 amperes. Examining the values given on Table, the 2.0 mm 2 or No. On convenience outlet receptacle, the National Electrical Code provides that, " Each single receptacle shall be considered at no less than 180 watts rating."Ģ. under the column of fuse and breaker rating, the 20 amperes fuse can safely carry a maximum load of 16 amperes the 80 % of 20 amperes fuse can safely carry a maximum load of 16 amperes the 80% of 20 amperes load permitted by the National Electrical Code on No. Determine the Over Current fuse protection. For 9.39 amperes, use 2 pieces 3.5 mm 2 or No. Determine the Size of the Conductor wire. Determine the Maximum Expected Current Load:Ĥ. considering that there are two plug outlet, the total number of plug will be:ģ. From Figure above, there are 6 convenience receptacles for small appliance load. It simply mean that, each convenience outlet, is considered to have a maximum load of not less than 180 watts per plug or gang. " For each single receptacle shall be considered at no less than 180 watts rating." therefore the use of 2.0 mm 2 or No.14 TW is safe. 80 % of 15 is 12, the maximum allowable load of the circuit sufficient enough to carry the 3.48 amperes computed load for a maximum 100 watts per light outlet. In Table, the maximum ampacity load of a or 2.0 mm 2 No.14 AWG copper wire is 15 amperes. "Ampacity of the connected load shall not exceed 80% of the amperage capacity of the conductor and the fuse." determine the size or rating of the fuse protective device. therefore, specify 13 mm diameter conduit pipe.ĥ. The smallest diameter of a conduit pipe that could accommodate up to 3 pieces of No.14 TW conductor wire is 13 mm diameter. 14 TW copper wire having an ampacity of 15 amperes that is much largr than the 3.48 amperes computed maximum load.Ĥ. Determine the size of conductor wire for circuit - 1.
"100 watts shall be the maximum load for each household lighting outlet."Īdopting the 100 watts per lighting outlet we have:ģ. The National Electrical Code provides that: By direct counting, there are 8 light outlets. From the Figure above, determine the number of lighting outlets. size or rating of the fuse protective deviceġ.size of the branch circuit wire for lighting outlets.A single family dwelling is to be circuited with the following requirements as shown on the figure above.
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